Q. According to size, drill can be classified as______
A. micro drill
B. moderate drill
C. large drill
D. all of the mentioned
.
Answer: D
Explanation: Micro drill, moderate drill and large drill are the types of drill according to size. Generally, this size is expressed in micron or in mm.
Q. When the size of the drill is around 25 to 500 micron,________ is used.
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: A
Explanation: Micro drill has a size from 25 to 500 micron as per classification.
Q. When the size of the drill is around 3 to 25 mm,________ is used.
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: B
Explanation: Moderate drill has a size of 3 to 25 mm as per the classification.
Q. When the size of the drill is around 25 to 40 mm,________ is used.
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: C
Explanation: Generally, the large drill drill has a size from 25 to 40 mm as per classification.
Q. Which of the following drill is most widely used?
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: B
Explanation: Moderate type of drill is most widely used as it has medium size of drill- not too large and not too short.
Q. 1 mm = ______ micron.
A. 10
B. 100
C. 1000
D. none of the mentioned
.
Answer: C
Explanation: It is the simple mathematical conversion. 1 mm = 1000 micron and 1 micron = 0.001 mm.
Q. For large drills, large force should be applied.
A. true
B. false
.
Answer: A
Explanation: Large drills need large force as it has large l/d ratio.
Q. In industry, which type of drill is most useful?
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: B
Explanation: In industry, moderate type of drill is most widely used as it has medium size of drill and again it doesn’t need large force like large drill.
Q. For large drill, how much torque is needed?
A. small
B. moderate
C. large
D. none of the mentioned
.
Answer: C
Explanation: For large drill large force is needed. As torque=force*displacement so torque is directly proportional to the force. So we need large torque for large drill.
Q. For large drill, firstly hole is made by drill and then it is enlarged by boring operation.
A. true
B. false
.
Answer: A
Explanation: It is the working procedure for making large drill. Drill just make the hole. Boring is specially used for enlarging the drill that has already made by drill.
1Q. Large drill is a mass production machine.
A. true
B. false
.
Answer: B
Explanation: It is used only for specific purpose as it needs very large force and torque.
1Q. Which of the following can be used for mass production?
A. micro drill
B. moderate drill
C. large drill
D. none of the mentioned
.
Answer: B
Explanation: Moderate drill can be used for mass production as it has medium size of drill and it don’t need too large force like large drill.
Q. The flutes are provided for removal of chips.
A. true
B. false
.
Answer: A
Explanation: It is the property of it. There is a sharp blade which is there along with edge of the flute known as teeth.
Q. Which of the following is most commonly used?
A. single flute drill
B. two flute drill
C. three or four flute drill
D. none of the mentioned
.
Answer: B
Explanation: Two flute drill is commonly used because it is very versatile and has wide applications.
Q. Which of the following is rarely used?
A. single flute drill
B. two flute drill
C. three or four flute drill
D. none of the mentioned
.
Answer: A
Explanation: Single flute drill is rarely used as it has very limited applications.
Q. Single flute drill is ______
A. very light
B. very rigid
C. can’t say anything
D. none of the mentioned
.
Answer: A
Explanation: It is very rigid that’s the reason why it has very small applications.
Q. Which of the following is the example of single flute drill?
A. deep hole drill
B. crank shaft hole drill
C. both deep hole drill and crank shaft hole drill
D. none of the mentioned
.
Answer: C
Explanation: Both are examples of single flute drill. Deep hole drilling is used with large length and comparatively small diameter of drill. Crank shaft hole drill has also wide applications.
Q. Which of the following is also known as slot drill?
A. single flute drill
B. two flute drill
C. three or four flute drill
D. none of the mentioned
.
Answer: C
Explanation: Generally 3 or 4 flute drill is also known as slot drill. Slot drill is a double cutting drill with flat end. It has two radial cutting edges.
Q. Gun drill is the example of______
A. single flute drill
B. two flute drill
C. three or four flute drill
D. none of the mentioned
.
Answer: A
Explanation: It can be easily understood from the classification. Gun drill is a fluted drill. These are used deep drilling.
Q. Sometimes soft drills are used to reduce the load path tooth.
A. true
B. false
.
Answer: A
Explanation: It is the application of soft drill. It is not used for heavy purpose. It is used mostly to reduce the load path tooth.
Q. Slot drills are used for making holes with flat ends.
A. true
B. false
.
Answer: A
Explanation: It is the application of slot drill. It consists of two radial edges.
Q. Flutes are the spiral groove, which run to the length of the drill.
A. true
B. false
.
Answer: A
Explanation: This is the property of flute.The flute allows us to remove material from the metal.
Q. Helix angle also governs the rack angle.
A. true
B. false
.
Answer: A
Explanation: This is true. The angle between the helix and axial line on the right is known as helix angel.
Q. For cutting ductile material with a long chip, ______ helixangle is necessary.
A. small
B. moderate
C. long
D. none of the mentioned
.
Answer: C
Explanation: Long helix angle is used for cutting ductile materials with a long chip.
Q. Large helix angle ensures the _______ in cutting force.
A. increment
B. reduction
C. can’t say anything
D. none of the mentioned
.
Answer: B
Explanation: It is the property of it. Helix angles are used in power transfer and in motion conversation in mechanical engineering.
Q. For spade drill, ______ helix angle is used.
A. small
B. large
C. zero
D. none of the mentioned
.
Answer: C
Explanation: Zero helix angle is used for this purpose.Spade drill is a two fluted drill. The external flute provide efficient chip removal.
Q. For hard materials, ______ helix angle is used.
A. small
B. large
C. zero
D. none of the mentioned
.
Answer: A
Explanation: Small helix angle is used for this purpose. In screws, helical gears and warm gears, we uses this helix angle.
Q. For micro drill, ______ helix angle is used.
A. small
B. large
C. zero
D. none of the mentioned
.
Answer: C
Explanation: Zero helix angel is used for this purpose. Helix angel is like a angel between tangent to a helix and an axial line on the right.
Q. Which helix angle is used for deep hole drilling?
A. small
B. large
C. zero
D. none of the mentioned
.
Answer: B
Explanation: Large helix angel is used for this purpose. Zero helix angel are used for small drilling.
Q. Which helix angle is used for making holes in very soft materials?
A. small
B. large
C. zero
D. none of the mentioned
.
Answer: B
Explanation: Large helix angel is used for this purpose as it can make make deep holes easily without any extra effort.
Q. According to the helix angel of the flutes, drill can be classified as_____
A. small helix
B. large helix
C. zero helix
D. all of the mentioned
.
Answer: D
Explanation: Drill can be classified in number of ways. based on helix angel, based on number of flutes, based on materials, based on size on so on. Based on helix angel, it can be classified as small helix, large helix and zero helix.
Q. If we increase the helix angle, strength of drill will______
A. increase
B. decrease
C. not affected
D. none of the mentioned
.
Answer: B
Explanation: There is an inverse relationship between helix angel and strength of drill. If we increase the helix angel, strength of drill will decrease and vice versa.
1Q.Chip disposal will be better If we _______ the helix angle.
A. increase
B. decrease
C. can’t say anything
D. none of the mentioned
.
Answer: A
Explanation: It is the property of helix angel and if we decrease the helix angel it will affect chip disposal rate in a negative way.
1Q. What is the range of the usual helix angle?
A. 10 to 25
B. 20 to 35
C. 45 to 60
D.none of the mentioned
.
Answer: B
Explanation: 20 to 35-This is the usual range for usual helix angel.
1Q. What is the range of the large helix angle?
A. 10 to 25
B. 20 to 35
C. 45 to 60
D. none of the mentioned
.
Answer: C
Explanation: 45 to 60-This is the usual range for usual helix angel.
1Q. If we increase the helix angle, rack angle will______
A. increase
B. decrease
C. not affected
D. none of the mentioned
.
Answer: A
Explanation: There is a direct relationship between helix angel and rack angel. If we increase the helix angel, rack angel will also increase and vice versa.
Q. If l/d ratio is too large, then drill becomes_______
A. weak
B. strong
C. very sharp
D. none of the mentioned
.
Answer: A
Explanation: The large l/d ratio weaken the drill. If we have very long drill with small diameter then it can’t perform drilling operation more accurately.
Q. If l/d ratio is too short, then chip removal will be difficult.
A. true
B. false
.
Answer: A
Explanation: Chip removal will be difficult if this ratio is too short. Short l/d ratio weakens the drilling and reduce the performance. So the chip removal will be difficult.
Q. Long drills are used for deep holes.
A. true
B. false
.
Answer: A
Explanation: As per the definition of long drill. Long drills has high l/d ration. So it can make high deeply holes.
Q. For general purpose, l/d ratio should be_____
A. 5 to 10
B. 10 to 20
C. more than 20
D. none of the mentioned
.
Answer: A
Explanation: For general purpose, the ratio should be 5 to Q. The drills containing these ratio generally used in ordinary performances.
Q. Which of the following can also be termed as center drill?
A. general drill
B. short drill
C. long drill
D. none of the mentioned
.
Answer: B
Explanation: Short drill can also be termed as centerr drill.
Q. For long drills, l/d ratio should be more then 2Q.
A. true
B. false
.
Answer: A
Explanation: For long drills, this ratio should be more than 2Q. For general purpose it should have ratio of 5 to Q.
Q. For small drill, l/d ratio should be 8 to Q.
A. true
B. false
.
Answer: B
Explanation: This is false. For small drill, l/d ratio should be 2 or Q.
Q. According to the shank type, drill can be classified as______
A. straight shank
B. taper shank
C. both taper shank and straight shank
D. none of the mentioned
.
Answer: C
Explanation: Both taper shank and straight shank are the type of shank drill. Brace shank, straight shank, hex shank etc. are the type of shanks.
Q. In ______ type, drill is held in spindle directly.
A. straight shank
B. taper shank
C. can’t say anything
D. none of the mentioned
.
Answer: B
Explanation: In taper type, drill is held in spindle directly. Taper shank drill is like a general purpose drill.
Q. In _______ type, drill is held in chuck.
A. straight shank
B. taper shank
C. can’t say anything
D. none of the mentioned
.
Answer: A
Explanation: In straight type, drill is held in chuck. It is also known as reduced shank or blacksmith’s drill.
Q. According to specific use, drill can be classified as______
A. center drill
B. step drill
C. both center drill and step drill
D. none of the mentioned
.
Answer: C
Explanation: Both are the examples of specific use drill. These special purpose drilling machines are intended for drilling multiple holes at a single setting.
Q. Subland drill is type of drill according to______
A. l/d ratio
B. shank type
C. specific use
D. none of the mentioned
.
Answer: C
Explanation: Subland drill is the example of special purpose drilling machine. Apart from this, turret, micro drill press and muliple spindle drilling machines are also an example of specific purpose drilling machine.
Q. Which of the following drill is very short drill?
A. center drill
B. subland drill
C. step drill
D. none of the mentioned
.
Answer: A
Explanation: Center drill is very short drill. Subland drill and step drill are large as compare to center drill.
Q. Which of the following is not true for center drill?
A. the hole is used to support the center
B. it is the type of drill according to specific use
C. one taper has to be made here
D. none of the mentioned
.
Answer: D
Explanation: All the mentioned sentences are true. It has a taper and also it is a specific purpose drill machine. It is short drill.
Q. In center drill, center has to be mounted on______
A. headstock
B. tailstock
C. headstock or tailstock
D. none of the mentioned
.
Answer: C
Explanation: The center can be mounted on either headstock or tailstock. Headstock and tailstock both are mounted on the bed.
Q. In which of the following, l/d ratio is very long?
A. half round drill
B. gun drill
C. both half round drill and gun drill
D. none of the mentioned
.
Answer: C
Explanation: Here l=length and d=diameter. In both half round drill and gun drill this ratio is very long as they have large value of length as compare to diameter.
Q. How many cutting edges are there in half round drill and gun drill?
A. one
B. two
C. may be one or two
D. none of the mentioned
.
Answer: A
Explanation: One edge is there in these both half round drill and gun drill. In these both drills, diameter is less as compare to length.
Q. How many flutes are there in half round drill and gun drill?
A. one
B. two
C. may be one or two
D. none of the mentioned
.
Answer: C
Explanation: One or two flutes are there in these both machines. These both machines are specific purpose machines used for a specific purpose.
Q. In half round drill, base is weak.
A. true
B. false
.
Answer: B
Explanation: This is false. The base is very strong in half round drill.
Q. Which of the following is a pipe like cutting tool?
A. center drill
B. half round drill
C. gun drill
D. none of the mentioned
.
Answer: D
Explanation: Trepanning tool has this structure. It structure looks like a pipe.
1Q. Trepanning is feasible for hard materials.
A. true
B. false
.
Answer: B
Explanation: This is false. Trepanning is not feasible for hard materials. It is feasible for soft material.
Q. Which of the following are the cutting parameters used in drill?
A. cutting speed
B. feed
C. depth of cut
D. all of the mentioned
.
Answer: D
Explanation: All are the cutting parameters used in drill. Apart from these parameters, machining time, metal removal rate are also cutting parameters which are used in drill.
Q. Which of the following is considered as the peripheral speed of the drill?
A. cutting speed
B. feed
C. depth of cut
D. none of the mentioned
.
Answer: A
Explanation: This is the definition of cutting speed. If you know the diameter of the drill and rpm of the drill, you can easily calculate the cutting speed.
Q. Cutting speed generally express in_____
A. meter
B. meter/minute
C. meter*minute
D. none of the mentioned
.
Answer: B
Explanation: Cutting speed is simply a speed. So, its unit should be match with speed’s unit.
Q. Formula for cutting speed is______
d=diameter of drill in mm, n=rpm of drill.
A. (d*n)/1000
B. (Q.14*d*n)/1000
C. Q.14*d*n
D. none of the mentioned
.
Answer: B
Explanation: Though cutting speed is peripheral speed the distance covered through it must be equal to Q.14*d. N is rpm and 1000 is there as we are measuring it in mm.
Q. The ______ of a drill is the distance the drill moves into the work at each revolution of the spindle.
A. depth of cut
B. feed
C. cutting speed
D. none of the mentioned
.
Answer: B
Explanation: This is the definition of feed. It is a distance/revolution.
Q. The feed may be expressed in______
A. mm/revolution
B. mm*revolution
C. mm
D. none of the mentioned
.
Answer: A
Explanation: As per its definition, feed is the distance per revolution. So its unit should be match with this formula..
Q. ______ is equal to half the diameter of the drill used.
A. feed
B. depth of cut
C. machining time
D. none of the mentioned
.
Answer: B
Explanation: This is the definition of depth of cut. Its simply a distance. Here one point is there, we always talk in terms of diameter in drill, never in terms of radius.
Q. Depth of cut can be expressed in______
A. mm
B. mm/revolution
C. mm/minute
D. none of the mentioned
.
Answer: A
Explanation: It is simply a distance and so its unit should be match with distance’s unit.
Q. The formula for depth of cut is______
d=diameter of the drill.
A. d/4
B. d/2
C. d
D. 2d
.
Answer: B
Explanation: Depth of cut is equal to half the diameter of the drill used. So if d is the diameter of drill then its formula must be equal to d/Q..
Q. If s2=feed per revolution, s1=feed per minute, n=rpm.
Which of the following is mathematically right?
A. s1=s2*n
B. s2=s1*n
C. s1*s2=n
D. none of the mentioned
.
Answer: A
Explanation: It can be solved by equating units both sides. Left side unit = feed/minute and Right side unit = feed / revolution * revolution/minute. So overall unit of right side = feed/minute. So, left side unit=right side unit.
1Q. Machining time is expressed in______
A. mm/minute
B. minute*minute
C. minute
D. none of the mentioned
.
Answer: C
Explanation: Machining time is simply a time. So its unit must be match with time’s unit.
1Q. If l=length of travel of the drill in mm, n=rpm of the drill, s= feed per revolution of the drill in mm. Then machining time can be given as_____
A. (l*n)/s
B. (l*s)/n
C. l/(n*s)
D. none of the mentioned
.
Answer: C
Explanation: L/(n*s)- This is the right formula for calculating machining time. Here l is expressed in mm, n is revolution/minute and s is expressed in mm. So by putting these all units in machining time’s formula we get the unit of the whole expression as minute. So our formula is right.
1Q. Metal removal rate can be given as_____
A. (mm*mm*mm)/min
B. (mm*mm*m)/revolution
C. mm/revolution
D. mm/minute
.
Answer: A
Explanation:
Metal removal rate = area of metal removed*rpm*feed/revolution and it equal to (Q.14*d^2/4)*n*feed/revolution. From this, we can easily derive the expression.
Q. Which of the following operation is performed to ensure the correct location of a hole by making it concentric with the axis of rotation?
A. parting
B. tapping
C. boring
D. none of mentioned
.
Answer: C
Explanation: This is the characteristic of boring. After the hole is made by drilling operation, boring is carried out. It is generally done to enlarge the diameter of the hole.
Q. Which of the following operations can be done by same tool?
A. reaming and tapping
B. drilling and facing
C. counterboring and spot facing
D. none of the mentioned
.
Answer: C
Explanation: Counterboring and spot facing can be performed by same tool. Counter boring is an operation which nis carried out for providing recess for nuts or bolt heads.
Q. Reaming doesn’t improve the surface finish.
A. true
B. false
.
Answer: B
Explanation: Reaming improves the surface finish. It generally enlarge the holes with great accuracy and give better dimensional accuracy-better surface finish.
Q. Which of the following process is performed to provide seating for washer?
A. counterboring
B. spot facing
C. tapping
D. none of the mentioned
.
Answer: B
Explanation: As per the definition of spot facing process. In spot facing operation, some specific part of the workpiece is faced. It gives better flat,smooth surface to that workpiece.
Q. To produce more accurate holes, which of the following operation should be performed first?
A. drilling
B. reaming
C. centering
D. boring
.
Answer: C
Explanation: As per the characteristic of all these operation, centering should be performed first before drilling, reaming and boring in order to produce more accurate holes. Center drill makes a hole. Now, this hole behave as a center of rotation for mentioned rest 3 operations.
Q. To produce more accurate holes, which of the following operation should be performed last?
A. drilling
B. reaming
C. centering
D. boring
.
Answer: B
Explanation: As per the characteristic of all these operation, reaming should be performed last in order to produce more accurate holes. By using all rest 3 method, we make the hole with almost accuracy. But for final finish and extremely high accuracy, reaming is performed at the last.
Q. Tapping is a forming process.
A. true
B. false
.
Answer: A
Explanation: As per the definition of taping process. The main advantage of taping is that is requires less operating conditions.
Q. Which of the following process requires abundant coolant?
A. drilling
B. tapping
C. boring
D. none of the mentioned
.
Answer: B
Explanation: Tapping needs abundant coolant. Cutting fluid is the coolant generally designed for metal working process.Different types of fluids are there like oil, gel, aerosols and so on.
Q. Tapping process is carried out on ______ machines.
A. drilling
B. tapping
C. both drilling and tapping
D. none of the mentioned
.
Answer: C
Explanation: Tapping process is carried out on both drilling and tapping machines. Taper is a shape which is produced and it has different diameter at both the ends
Q. Which of the following operation is carried out for cutting internal threads?
A. drilling
B. tapping
C. boring
D. none of the mentioned
.
Answer: B
Explanation: Tapping is carried out for cutting internal threads because tapping process generally don’t need high operating conditions. They require less operating conditions.
Q. Tapping is carried out by using tap tool.
A. true
B. false
.
Answer: A
Explanation: As per the definition of this process. A tap is also applied for cutting and forming female part of the mating pair like nuts.
Q. Which of the following operation is carried out to make the hole dimensionally more accurate?
A. reaming
B. tapping
C. boring
D. none of mentioned
.
Answer: A
Explanation: Reaming is used for this purpose. Reaming also improve the surface finish which is its extra advantage.
Q. Which of the following operation is performed to provide recess for bolt heads or nuts?
A. counterboring
B. spot facing
C. tapping
D. none of the mentioned
.
Answer: A
Explanation: As per the definition of counterboring process. Generally, counter boring is a process carried out for delivering recess for nuts etc.
Q. Reaming is carried out by using a reamer.
A. true
B. false
.
Answer: A
Explanation: It is carried out by a reamer. Reamer is a cutting tool generally used for enlarging the hole with great accuracy.
Q. Which of the following process is carried out to provide seating for head of screw?
A. counterboring
B. countersinking
C. tapping
D. none of the mentioned
.
Answer: B
Explanation: As per the definition of countersinking process. To make the cone or taper shape at the entrance of the hole, this process is used.
Q. Countersinking process is carried out by using countersink tool.
A. true
B. false
.
Answer: A
Explanation: Countersink tool is used for countersinking process. Counter sinks are available as single flute and and multi flute tools.
Q. Taping process employs high operating conditions.
A. true
B. false
.
Answer: B
Explanation: This is false. Taping process employs low operating conditions.
Q. To produce more accurate holes, which of the following operation should be performed third?
A. drilling
B. reaming
C. centering
D. boring
.
Answer: D
Explanation: As per the characteristic of all these operation, boring should be performed third in order to produce more accurate holes. Boring is used to make hole of size for which drill is not available. It generally enlarge the hole.
Q. To produce more accurate holes, which of the following operation should be performed second?
A. drilling
B. reaming
C. centering
D. boring
.
Answer: A
Explanation: As per the characteristic of all these operation, drilling should be performed second in order to produce more accurate holes. Drilling doesn’t make hole of exact dimension and accuracy. For exact dimension boring is carried out and for final dimensional accuracy reaming is carried out.
Q. Which of the following operation is used to enlarge the previously drilled hole?
A. reaming
B. tapping
C. boring
D. none of mentioned
.
Answer: C
Explanation: Boring is used for this purpose. Apart from this, boring aslo insures the exact location of a hole. It makes the hole concentric with the axis of rotation.
Q. A hole is being drilled with 5 mm drill at a feed of 0.1 mm/revolution and rpm is 200. Calculate the metal removal rate (m) in mm3/minute.
A. 39Q.5
B. 785
C. 1570
D. none of the mentioned
.
Answer: A
Explanation: Here, we have the value of diameter, feed and rpm. So, from the formula, m= ( Q.14*d*d*f*n) / 4, we can easily get the value of metal removal rate.
Q. If drill is Q.5 mm, feed is 0.35 mm/revolution and metal removal rate is 40 mm3/minute. Then find out the value of rpm.
A. 4Q.6
B. 2Q.3
C. 9Q.2
D. 1Q.65
.
Answer: B
Explanation: From the formula, m= ( Q.14*d*d*f*n) / Q. From this formula, we can easily calculate rpm. Rpm means revolution per minute.
Q. If drill is Q.5 mm, metal removal rate is 65 mm3/minute and rpm is 130.Then find the value of feed in mm/revolution.
A. 0.02
B. 0.2
C. 0.04
D. 0.4
.
Answer: A
Explanation: Feed is the distance the drill moves into the work at each revolution of the spindle. From the formula, m= ( Q.14*d*d*f*n) / 4, we can easily calculate feed.
Q. If metal removal rate is 120 mm3/minute, rpm is 105 and feed is 0.1 mm/revolution. Then find the value of drill in mm.
A. 1Q.6
B. Q.8
C. Q.6
D. Q.9
.
Answer: B
Explanation: From the formula, m= ( Q.14*d*d*f*n) / 4, we can calculate the value of drill.
Q. If value of the diameter of the drill (d2) = 10mm, then find the value of the depth of cut (d1).
A. 5
B. 10
C. 20
D. none of the mentioned
.
Answer: A
Explanation: Value of diameter of the drill is always twice to that the value of the depth of cut. From the formula, d1= d2/Q.
Q. The diameter of the drill is 15 mm and rpm of drill is Q. Find the value of cutting speed in meter/minute.
A. 23Q.5
B. 0.2355
C. 0.075
D. 75
.
Answer: B
Explanation: From the formula, cs = (Q.14*d*n) /1000. Cutting speed is the peripheral speed of the drill.
Q. Rpm is 10 and feed per revolution (f2) is Q. Then find the value of feed per minute (f1).
A. 2
B. 4
C. 1
D. none of the mentioned
.
Answer: D
Explanation: Rpm = f1/fQ. Here rpm=10 and f2=Q. So value of f1 should be 50.
Q. If depth of cut is 20 mm, then find the value of diameter of the drill.
A. 10
B. 20
C. 40
D. none of the mentioned
.
Answer: C
Explanation: Depth of cut=diameter/Q. It is simply a distance.
Q. Feed per minute (f1) is 20 and rpm (n) is Q. Then find the value of feed per revolution (f2).
A. 2
B. 4
C. 1
D. 0.5
.
Answer: B
Explanation: Rpm = f1/fQ. Here f1=20 and n=Q. So, f2 should be Q.
Q. If t=2minute, n=2rpm and s=5 mm. Then find the value of l. t=machining time in minute, l=length of travel of the drill in mm, n= rpm of the drill and s=feed per revolution of the drill in mm.
A. 5
B. 10
C. 20
D. none of the mentioned
.
Answer: C
Explanation: From the formula, t= l / (n*s). Here t=2, n=2 and s=Q. Put all these values with their units in the mentioned equation,you will easily get the answer as 20 mm.
1Q. If d=2, n=1 and f=Q. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
A. Q.14
B. Q.28
C. 1Q.56
D. none of the mentioned
.
Answer: B
Explanation: From the formula, m= (Q.14*d*d*n*f) / 4, we can easily get the value of m. Metal removal rate means the rate at which the metal is removed during the operation.
1Q. If d=2, n=2 and m=Q. Then find the value of f. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
A. 0.238
B. 0.477
C. 0.119
D. none of the mentioned
.
Answer: B
Explanation: From the formula, m= (Q.14*d*d*n*f) / 4, we can easily get the value of feed. Feed may also be expressed as feet per minute or mm/minute.
1Q. If m=5, n=2 and f=Q. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
A. Q.03
B. Q.065
C. 0.266
D. none of the mentioned
.
Answer: B
Explanation: From the formula, m= (Q.14*d*d*n*f) / 4, we can easily find the value of m.
1Q. If cs=0.942 and d=60, then find the value of n. d=diameter of drill in mm, n=rpm and cs=cutting speed in mm/minute.
A. 1Q.7
B. 15700
C. 5
D. 5000
.
Answer: C
Explanation: From the formula, cs = (Q.14*d*n) /1000, we can easily find value of n. N means rpm-revolution per minute. It is an important term in any operation.
Q. A hole is being drilled with Q.5mm drill at a feed of 0.3 mm/revolution and rpm is 70. Calculate the metal removal rate in mm3/minute.
A. 1Q.5
B. 37
C. 74
D. 148
.
Answer: B
Explanation: Metal removal rate means the rate at which the metal is removed during the operation. From the formula, m= ( Q.14*d*d*f*n) / 4, we can easily calculate metal removal rate.
Q. If drill is 2 mm, feed is 0.2 mm/revolution and metal removal rate is 50 mm^/minute. Then find out the value of rpm.
A. 31Q.4
B. 15Q.2
C. 7Q.6
D. 3Q.8
.
Answer: C
Explanation: From the formula, m= ( Q.14*d*d*f*n) / Q. Put all the given values with their respective units in the above equation and you will get the value of n as 7Q.6 .
Q. If drill is Q.15 mm, metal removal rate is 55 mm3/minute and rpm is 170.Then find the value of feed in mm/revolution.
A. 0.02
B. 0.2
C. 0.04
D. 0.4
.
Answer: C
Explanation: During each revolution of spindle drill moves into the work. That distance is known as the feed.From the formula, m= ( Q.14*d*d*f*n) / Q.
Q. If metal removal rate is 100 mm3/minute, rpm is 165 and feed is 0.01 mm/revolution. Then find the value of drill in mm.
A. Q.78
B. Q.41
C. 1Q.3
D. 7Q.8
.
Answer: A
Explanation: From the formula, m= ( Q.14*d*d*f*n) / Q. By substituting all the given values in the above equation, we can easily get the value of drill.
Q. If diameter of the drill is 20 mm. Then find the value of depth of cut in mm.
A. 20
B. 10
C. 40
D. none of the mentioned
.
Answer: B
Explanation: Depth of cut=diameter/Q. Depth of cut is equal to half the diameter of the drill used.
Q. The diameter of the drill is 20 mm and rpm of drill is Q. Find the value of cutting speed in meter/minute.
A. 0.628
B. 628
C. 0.2
D. 200
.
Answer: A
Explanation: From the formula, cs = (Q.14*d*n) /1000. Cutting speed in a drilling operation is taken as the peripheral speed of the drill.
Q. Feed per minute (f1) is 10 and feed per revolution (f2) is Q. Then find the value of rpm.
A. 2
B. 4
C. 1
D. 0.5
.
Answer: A
Explanation: Rpm = f1/fQ. Here, f1=10 and f2=Q. We can easily get the value of rpm as Q.
Q. If the depth of cut (d1) is 10mm, then find the value of the diameter of the drill (d2).
A. 5
B. 10
C. 20
D. none of the mentioned
.
Answer: C
Explanation: From the formula, d1= d2/Q. Here d1=Q. So, d2 sholud be Q.
Q. If l=10mm, n=2 rpm and s=5 mm. Then find the value of t. t=machining time in minute, l=length of travel of the drill in mm, n= rpm of the drill and s=feed per revolution of the drill in mm.
A. 0.5
B. 1
C. 2
D. none of the mentioned
.
Answer: B
Explanation: From the formula, t= l / (n*s). By putting all the given values in the above equation, we can easily get the value of machining time as 1 minute.
Q. If l=10mm, n=2 rpm and t=0.5 minute. Then find the value of s. t=machining time in minute, l=length of travel of the drill in mm, n= rpm of the drill and s=feed per revolution of the drill in mm.
A. 5
B. 10
C. 20
D. none of the mentioned
.
Answer: B
Explanation: From the formula, t= l / (n*s), we can calculate the feed per revolution. Feed per revolution may be defined as the axial distance moved by the drill into the work per revolution.
1Q. If l=20 mm, t=2 minute and s=5 mm. Then find the value of t. t=machining time in minute, l=length of travel of the drill in mm, n= rpm of the drill and s=feed per revolution of the drill in mm.
A. 0.5
B. 1
C. 2
D. none of the mentioned
.
Answer: C
Explanation: From the formula, t= l / (n*s). Substitute all the given values in the above equation and you can get the value of t as Q.
1Q. If d=1, n=1 and f=Q. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
A. 0.08
B. 1
C. 0.3184
D. none of the mentioned
.
Answer: C
Explanation: From the formula, m= (Q.14*d*d*n*f) / Q. Here d,n and f are given. Substitute these values in above equation, you will easily get value of m as 0.3184 .
1Q. If d=2, n=4 and f=Q. Then find the value of m. d= diameter of drill in mm, n=rpm, f=feed per revolution in mm and m=metal removal rate in mm3/minute.
A. 0.798
B. 1
C. 0.6369
D. none of the mentioned
.
Answer: A
Explanation: From the formula, m= (Q.14*d*d*n*f) / Q. Substitute all tyhe given values in the above equation and you will easily get the value.
1Q. If cs=1 and n=40, then find the value of d. d=diameter of drill in mm, n=rpm and cs=cutting speed in mm/minute.
A. Q.96
B. Q.98
C. 1Q.92
D. none of the mentioned
.
Answer: A
Explanation: From the formula, cs = (Q.14*d*n) /1000. Substitute all tyhe given values in the above equation and you will easily get the value of d.
Q. Which of the following is used for machining larger jobs?
A. shaper
B. planer
C. can’t say anything
D. none of the mentioned
.
Answer: B
Explanation: Planer is used for the purpose of machining too large and heavy jobs. There is a table in planer known as platen on which the work piece is fixed firmly and the operation is performed.
Q. Which of the following is used for machining smaller jobs?
A. shaper
B. planer
C. can’t say anything
D. none of the mentioned
.
Answer: A
Explanation: Shaper is used for the purpose of machining smaller jobs. It is mainly used for producing flat and plan surfaces.
Q. Which of the following machine is primarily intended for producing flat surfaces?
A. shaper
B. drilling
C. lathe
D. none of the mentioned
.
Answer: A
Explanation: Shaper is intended for this purpose. It was invented in 1836 by James Nasmyth.
Q. Which of the following operation can be performed in shaper?
A. gear cutting
B. keyways cutting
C. curvilinear contours
D. all of the mentioned
.
Answer: D
Explanation: All mentioned operations can be performed in shaper. Although it is used mainly for producing flat surfaces but its a versatile machine and can be used for other purposes too.
Q. In shaper, the job is kept_____
A. stationary
B. rotating
C. reciprocating
D. none of the mentioned
.
Answer: A
Explanation: The job is kept stationary in this machine. In shaper, cutting tool moves in order to perform operations.
Q. In shaper, the cutting tool is made to reciprocate across the job.
A. true
B. false
.
Answer: A
Explanation: This is true. cutting tool moves in order to perform the work. Only forward movement is useful. Work is only done in forward movement.
Q. Which stroke is cutting stroke in shaper?
A. forward
B. return
C. can’t say anything
D. none of the mentioned
.
Answer: A
Explanation: Forward stroke is cutting stroke in shaper because only in forward stroke work-cutting is done.
Q. Which stroke is idle stroke in shaper?
A. forward
B. return
C. can’t say anything
D. none of the mentioned
.
Answer: B
Explanation: Return stroke is idle stroke in shaper because no useful work is done in this stroke.
Q. No useful work is done in forward stroke in shaper.
A. true
B. false
.
Answer: B
Explanation: In return stroke, no useful work is done. The return stroke is also known as idle stroke.
Q. At the end of one cycle, job is given a feed motion______ to the direction of tool movement.
A. parallel
B. perpendicular
C. anti-parallel
D. none of the mentioned
.
Answer: B
Explanation: At the end of one cycle, job is given a feed motion perpendicular to the direction of tool movement. Feed is the relative movement of the tool or work.
1Q. The depth of cut is given by lowering the tool relative to the job.
A. true
B. false
.
Answer: A
Explanation: This is true. Depth of cut is the thickness of metal that is removed in one cut.